String to int java.lang.NumberFormatException -

i have java program convert string int, rang of string 190520141618013381(above rang of int) when convert int java.lang.numberformatexception: thrown

stringbuffer stringbuffer = new stringbuffer(); stringbuffer.append(format.format(date)); stringbuffer.append(demandcount); int test_int = integer.parseint(stringbuffer.tostring()); // exception has been fixed putting                                  //long abc_i = long.parselong(abc); log.info("test_int: "+test_int); 

my question compiler should throw numberoutofrangexception(if exception available in api) instead java.lang.numberformatexception:, format of number(190520141618013381) right.

the string 190520141618013381 outside range of int doesn't match accepted format of int because long.

the compiler doesn't throw error, thrown @ runtime.

i believe correct comply documentation method.

btw don't use stringbuffer, replaced stringbuilder ten years ago.

imho storing date integer isn't idea in general.

---

a more efficient unique id contains time in millis this.

 private static final atomiclong ts_counter = new atomiclong();   public static long nexttimestamp() {       long time = system.currenttimemillis() * 1000;       long curr = ts_counter.get();       if (curr < time && ts_counter.compareandset(curr, time))           return time;       return ts_counter.incrementandget();  } 

this have time-in-millis * 1000 plus unique id. works fine if average less 1 million ids per second.