bit manipulation - How can I efficiently zero out the last 32 bits of a double in java? -

how can 0 out last 32 bits of double, in java, efficiently possible?

try this.

private static final long zero_out_last_32_bits = 0xffffffff00000000l;  public static void main(string[] args) {     double number = 2.5;      long numberbits = double.doubletolongbits(number);     double result = double.longbitstodouble(numberbits & zero_out_last_32_bits); } 

it zeroes out last 32 bits of binary representation of double using binary and operation.

however, make sure know , why doing - @ least expect explaining comment next code this.