How to separate and store elements from a string in c? -

i have open .txt file. suppose content of file is:

08123, (12/10/2010,m), (01/09/1990,d) 

i want store in different parameters of string 08123, "12/10/2010" , 'm', example:

int code = 08123; char date[10] = '12/10/2010'; char day = 'm'; 

also, last argument finishes ). how can iterate until line ends?

#include <stdio.h> #include <stdlib.h> #include <string.h>  typedef struct date {     char date[11];//+1 '\0'.     char day; } date;  typedef struct rec {     int code;     int dc;//number of date     date *dates; } record;  record *parse_rec(char *line){     static const char *sep = ", ";     static const int seplen = 2;//strlen(sep);     record *rec = malloc(sizeof(*rec));     if(rec){         int i, count = 0;         char *p;         for(p=strstr(line, sep);p;p = strstr(p+seplen, sep)){             ++count;         }         rec->dc = count;         rec->dates = malloc(count*sizeof(date));         rec->code = atoi(line);         line = strstr(line, sep) + seplen;         for(i=0;i<count;++i){             sscanf(line, "(%[^,],%c", rec->dates[i].date, &rec->dates[i].day);             line = strstr(line, sep) + seplen;         }     }     return rec; }  int main(void){     char line[1024];     file *fp = fopen("data.txt", "r");      fgets(line, sizeof(line), fp);     fclose(fp);      record *rec = parse_rec(line);     printf("code: %05d\n", rec->code);     for(int i=0;i < rec->dc; ++i){         printf("date : %s\n", rec->dates[i].date);         printf(" day : %c\n", rec->dates[i].day);     }     free(rec->dates);     free(rec);     return 0; }